If x=2+root 3 , xy=1 then find x/2-x+y/2-y
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Answered by
8
x=2+√3
xy=1
so,y=1/2+√3
=>y=2-√3
x/2-x+y/2-y
=(2+√3)/2-(2+√3+2-√3)/2+(2-√3)
=1+√3/2-2+2-√3
=2-√3/2(ans)
please mark as brainliest answer if you get help from this
xy=1
so,y=1/2+√3
=>y=2-√3
x/2-x+y/2-y
=(2+√3)/2-(2+√3+2-√3)/2+(2-√3)
=1+√3/2-2+2-√3
=2-√3/2(ans)
please mark as brainliest answer if you get help from this
Answered by
8
Answer:
-2
Step-by-step explanation:
Here,
x = 2 + √3,
And, xy = 1 ⇒ y = 1/x
By rationalizing,
Thus,
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