Math, asked by bestinvinod, 7 months ago

if x= 2-root 3,y=root 3 -root 2 and z =root 7 -root 4 find the value of x^3+y^3+z^3

Answers

Answered by saipavan018
0

Answer:

x^3+y^3+z^3 = 0.320620

(or)

(-24)-(11*Sqrt(2))-(6*Sqrt(3))+(19*Sqrt(7))

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