if x=2+root 3and xy=1 then x/root2+root x
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Find the value of square roots of x and y. Then use rationalization of denominator to find the value of y.
x = 2 + √3
xy = 1
y = 1 /(2 + √3) = (2 - √3)/[(2 - √3)(2 + √3)
= 2 - √3
Let √x = √a + √b
then x = 2 + √3 = a + b + 2 √ab
so a + b = 2 and ab = 3 /4
(a - b)² = 4 - 3 = 1
a - b = 1 => a = 3/2 b = 1/2
so √x = (√3 +1)/√2
√y = 1/√x = (√3 - 1)/√2
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