if x = (2+root3), find the value of x^2+ 1/x^2
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if x= 2+sqrt3
then
1/x=2-sqrt3 (by rationaliztion)
then (x+1/x)^2 = X^2+(1/X)^2 +2*x*(1/X)
that is (2+sqrt3 +2-sqrt3)^2=x^2 +(1/x)^2+2
4^2 -2=x^2+(1/x)^2
i.e, 14 is the answer
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1
Answer:
14
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