If x=2-root3 find the values of x-1/xwhole cube
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if x=2-√3
x-1/x³=?
put x =2-√3
2-√3-1 /(2-√3)³
1-√3 /26-15√3
rationalising the denominator
1-√3*26+15√3 /26-15√3*26+15√3
-19-11√3 /1
-(19+11√3)ans
x-1/x³=?
put x =2-√3
2-√3-1 /(2-√3)³
1-√3 /26-15√3
rationalising the denominator
1-√3*26+15√3 /26-15√3*26+15√3
-19-11√3 /1
-(19+11√3)ans
amir69:
this is wrong its answer is -24root3
my ans is right
otherwise prove that ur ans is right
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