If x=2- root3
find (x+1)2 (read as x+
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given
so x+1the whole squared=3-root3 the whole squared.
so x+1the whole squared=3-root3 the whole squared.
Gomisan:
wrong
sorry it's right but u shall do step by step as i have done
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x=2-√3
Therefore,(x+1)²=(2-√3+1)²
=(3-√3)²
By using the identity (a-b)²=a²-2ab+b²,we get
=3²-2*3*√3+(√3)²
=9-6√3+3
=12-6√3
=6(2-√3) surprisingly,it is same as 6x !
Ans=6(2-√3)
Therefore,(x+1)²=(2-√3+1)²
=(3-√3)²
By using the identity (a-b)²=a²-2ab+b²,we get
=3²-2*3*√3+(√3)²
=9-6√3+3
=12-6√3
=6(2-√3) surprisingly,it is same as 6x !
Ans=6(2-√3)
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