if x = 2+root3 then find x sq+1/x sq
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Answer:
If x = 2 + root 3 find the value of x square + 1 upon x square
x²+1/x²
= (2+√3)²+1/(2+√3)²
= (2)²+(√3)²+2(2)(√3)+1/(2)²+(√3)²+2(2)(√3)
= 4+3+4√3+1/4+3+4√3
= 7+4√3+1/7+4√3
= (7+4√3)²+1/7+4√3
= 49+48+8√3+1/7+√3
= 98+8√3/7+√3
Answered by
0
Answer:
If x = 2 + root 3 find the value of x square + 1 upon x square
x²+1/x²
(2+√3)²+1/(2+√3)²
(2)²+(√3)²+2(2)(√3)+1/(2)²+(√3)²+2(2)(√3)
4+3+4√3+1/4+3+4√3
7+4√3+1/7+4√3
(7+4√3)²+1/7+4√3
49+48+8√3+1/7+√3
98+8√3/7+√3
hope it helps you friend !!!!
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