Math, asked by yashika1234, 1 year ago

if x=2+root3 under cube root then x cube+1by x cube=?

Answers

Answered by Light1729
0
x³=(2+√3)³=26+15√3

and 1/x³=1/(26+15√3)=26-15√3 (by rationalising)

So, x³+1/x³=26+15√3+26-15√3=52

avinash32: wrong answer
avinash32: x^3=2+root3, 1/x^3=2-root3 then x^3+1/x^3=2
Light1729: its given x=2+√3
Answered by avinash32
0
given,x=2+root3 under cube root
x^3=2+root3
1/x^3=2-root3
x^3+1/x^3=2+root3 + 2-root3=2
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