if x=2+root3 under cube root then x cube+1by x cube=?
Answers
Answered by
0
x³=(2+√3)³=26+15√3
and 1/x³=1/(26+15√3)=26-15√3 (by rationalising)
So, x³+1/x³=26+15√3+26-15√3=52
and 1/x³=1/(26+15√3)=26-15√3 (by rationalising)
So, x³+1/x³=26+15√3+26-15√3=52
avinash32:
wrong answer
Answered by
0
given,x=2+root3 under cube root
x^3=2+root3
1/x^3=2-root3
x^3+1/x^3=2+root3 + 2-root3=2
x^3=2+root3
1/x^3=2-root3
x^3+1/x^3=2+root3 + 2-root3=2
Similar questions