if X=(2+root5)^1/2 +(2-root5)^1/2 and y=(2+root5)^1)2-(2-root5)^1)2then evaluate x^2 + y^2 solving on a paper must be easier
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Your question ,
if X=(2+root5)^1/2 +(2-root5)^1/2 and y=(2+root5)^1)2-(2-root5)^1)2then evaluate x^2 + y^2 solving on a paper must be easier
Your answer ,
82.4721359550302329904704
Explanation ,
Given ,
- X = ( 2 + √5 ) ^ ½ + ( 2 - √5 ) ^ ½
- Y = ( 2 + √5 ) ¹ x 2 - ( 2 - √5 ) ¹ x 2
- X² + Y² = ...?
Finding the value of 'X' ,
- X = ( 2 + √5 ) ^ ½ + ( 2 - √5 ) ^ ½
- X = ( 2 + 2.2360679775 ) ^½ + ( 2 - 2.2360679775 ) ^½
- X = 4.2360679775^ ½ + ( - 0.2360679775) ^ ½
- X = 2.05817102727 - 0.48586827175
- X = 1.57230275552
Finding the value of 'Y'
- Y = ( 2 + √5 ) ¹ x 2 - ( 2 - √5 ) ¹ x 2
- Y = ( 2 + 2.2360679775 ) x 2 - ( 2 - 2.2360679775 ) x 2
- Y = ( 4.2360679775 x 2 ) - ( - 0.2360679775 x 2 )
- Y = 8.472135955 - ( -0.472135955 )
- Y = 8.472135955 + 0.472135955
- Y = 8.94427191
Evaluating X² + Y² ,
- X² + Y² = ( 1.57230275552 )² + ( 8.94427191 )²
- = 2.4721359550157848904704 + 80.0000000000150481
- = 82.4721359550302329904704
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