Question

if x=[2+root5]^1/2+[2-root5]^1/2 y=[2+root5]^1/2+[2-root5]^1/2 then evaluate x^2+y^2 pls its urgent

Answer 1

Answer:

Step-by-step explanation:

Using the maths property:

(a+b)(a-b) = ;

x = (2+√5)1/2+(2-√5)1/2

Taking 1/2 as common;

x = (1/2) [(2+√5)+(2-√5)] = (1/2) [2+2];

x = 2;

y = (2+√5)1/2-(2-√5)1/2;

Taking 1/2 as common;

y = (1/2) [2+√5 - 2+√5]

y = (1/2) [2√5] = √5;

x^2+y^2 = 4+5 = 9

hope it helps

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