If x =2+root5 then find the value of x^2+1/x^2
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1
Here is ur answer....
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Answered by
3
by putting value of x in the equation
(2+root 5)^2+1/(2+root 5)^
=4+5+4root5+1/9+4root5
=((9+4root5)^2+1)1/9+4root5
=(81+80+1)/9+4root5
=(81)^/9+4root5
(2+root 5)^2+1/(2+root 5)^
=4+5+4root5+1/9+4root5
=((9+4root5)^2+1)1/9+4root5
=(81+80+1)/9+4root5
=(81)^/9+4root5
sutharya01:
In he third line...it is 1/9+4root5....how does it come...???!
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