Question

if x^2+x+1 =0 ,find the value of x^2015+x^2016

Answer 1

answer is -1........

Answer 2

Answer:

answer is 2

Step-by-step explanation:

$x^3 - y^3 = (x-y)(x^2+xy+y^2)\\x^3 - 1 = (x-1)(x^2+x+1)\\\frac{x^3-1}{x-1 } = x^2+x+1\\\frac{x^3-1}{x-1 } = 0\\x^3-1 = 0\\x^3 = 1\\x = 1\\1^2^0^1^5 + 1^2^0^1^6 = 1+1\\= 2$

SO the answer is 2