Question

If (x–2) (x+1) = ax2+bx+c, then find the value of a+b+c​

Answer 1

Answer:

-2

Step-by-step explanation:

(x–2) (x+1) = ax2+bx+c

1x^2 -1x -2 = ax2 + bx + c

So a = 1, b = -1 , c = -2

So a + b + c = 1 + (-1) + (-2)

So a + b + c = 1 - 1 -2

So a + b + c = -2

Hope that helps

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