Question

if x^2+x=1 then (x^5+8)/(x+1)=​

Answer 1

Answer:

(-1 ± 13*)/2

Step-by-step explanation:

if x^2 + x = 1 then find x^5 + 8/x + 1

x^2 = -x + 1

x^5

= x^2 * x^2 * x

= (-x + 1) * (-x + 1) * x

= x^3 - 2x^2 + x

= x * (-x + 1) - 2(-x + 1) + x= x - 1 + x + x + 2x -2 + x

= 5x - 3

the equation can be divided by x because x is not equal to 0.

(If x = 0, x^2 + x = 0)

1 = x^2 + x

1/x = x + 1

8/x = 8(x + 1) = 8x + 8

x^5 + 8/x + 1

= 5x - 3 +8x + 8 + 1

= 13x + 6

Let's solve x^2 + x = 1

x = (-1 ± )/213x + 6

= (-13 + 12 ± 13*)/2

= (-1 ± 13*)/2