Math, asked by nazmeenshaikh549, 1 year ago

If ( X-2),(X+2),(2X+1),(2X+19) are in proportion find the value of X

Answers

Answered by VishwasMiddha
22

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Answered by utsrashmi014
1

Concept

Let the two ratios a:bac:d be proportional,

i.e. a:b::c:d

In the ratio a:b::c:d

Product of means=product of extremes.

Ifa:b=c:d, then

a×d=b×c

Given

It is given that (X-2),(X+2),(2X+1),(2X+19) are in proportion

Find

We need to find the value of X

Solution

(X-2),(X+2),(2X+1),(2X+19) are in proportion

(X-2)(2X+19) = (X+2)(2X+1)

2X^2 +19X-4X-38 =2X^2 +X +4X+2

15X-38=5X+2

10X=40

X=40/10

X=4

Hence the value of X is 4

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