If ( X-2),(X+2),(2X+1),(2X+19) are in proportion find the value of X
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Concept
Let the two ratios a:bac:d be proportional,
i.e. a:b::c:d
In the ratio a:b::c:d
Product of means=product of extremes.
Ifa:b=c:d, then
a×d=b×c
Given
It is given that (X-2),(X+2),(2X+1),(2X+19) are in proportion
Find
We need to find the value of X
Solution
(X-2),(X+2),(2X+1),(2X+19) are in proportion
(X-2)(2X+19) = (X+2)(2X+1)
2X^2 +19X-4X-38 =2X^2 +X +4X+2
15X-38=5X+2
10X=40
X=40/10
X=4
Hence the value of X is 4
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