Question

If x=2 x=3 are the
roots of Q.E 3x² - 2axplus2bis equal to 0
then find the value of A and b​

Answer 1

Explanation:

3*2²-2*2*a+2b=0

3*3²-2*3*a+2b=0

a=15/8

b=_9/4

Answer 2

Answer:

x = 2 & x = 3

p(x) = 3x² - 2a x + 2b = 0

p(2) = 3 (2)² - 2 a(2) + 2b

0 = 12 - 4a + 2b

0 = 6 - 2a + b

2a - b = 6- (1)

p(3) = 3 (3)² - 2 a (3) + 2b

0 = 27 - 6a + 2b

6a - 2b = 27-(2)

equation(1) * 3 -equation (2)

6a - 3b = 18

6a - 2b = 27

- + -

-b = -9

b = 9

put the value in (1)

2a - b = 6

2a - 9 = 6

2a = 15

a = 15/2

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