If (x-2)(x+3)is the HFC of polynomial p(x)=(x^2-3x+2)(2x^2+7x+a). Q(x)=(x^2+4x+3)(3x^2-7x+b) find the value of a and b
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Answer:
In △ABC AB=AC
⇒∠B=∠C (Angles opposite to equal sides are equal)
Now using angle sum property
∠A+∠B+∠C=180
∘
⇒80
∘
+∠C+∠C=180
∘
⇒2∠C=180
∘
−80
∘
⇒∠C=
2
100
∘
=50
∘
now ∠C+∠x=180
∘
(Angles made on straight line (AC) are supplementary)
⇒50
∘
+∠x=180
∘
⇒∠x=180
∘
−50
∘
=130
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