Question

if (x-2)(x-4) are the factors of x³-ax²+14x+b then find values of a and b
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Answer 1

Answer:

see the attachment for answer

Answer 2

Ist Case

x-2=0

x=2

Put the value of x in the following polynomial :-

(2^3)-a(2^2)+(14×2)+b=0

8-4a+28+b=0

36-4a+b=0

36=4a-b ---------->>>>1st equation

2nd Case

x-4=0

x=4

Put the value of x in the following polynomial :-

(4^3)-a(4^2)+(14×4)+b=0

64-16a+56+b=0

120-16a+b=0

120=16a-b ---------->>>>2nd equation

Then Add both the equation:-

(4a+b)+(16a-b)=36+120

4a+b+16a-b=156

20a=156

a=156/20

a=78/10

4a+b=36

{4×(78/10)}+b=36

(312/10)+b=36

b=36-(312/10)

b=(360/10)+(312/10)

b=672/10

b=336/5

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