Question

if x^2+(x/5)+a^2 is a perfect square then a is ​

Answer 1

Answer:

$a=\frac{1}{10}$

Step-by-step explanation:

$x^2+\frac{x}{5}+a^2\\=x^2+2(x)(\frac{1}{10})+a^2$

According to this,

$a=\frac{1}{10} \\=> x^2+(\frac{x}{5}) +(\frac{1}{100})^2=(x+\frac{1}{10})^2$

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