If X^2-x-^6 and x^2+3x-18 have a common factor x-a find the value a
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Answered by
15
x² -x -6
=x² -3x +2x -6
=x(x -3) + 2(x -3)
=(x +2)(x -3)
now,
x² +3x -18
=x² +6x -3x -18
=x(x + 6) -3(x + 6)
=(x -3)(x + 6)
now you see (x -3) is common factor of given polynomials .
so a = 3
=x² -3x +2x -6
=x(x -3) + 2(x -3)
=(x +2)(x -3)
now,
x² +3x -18
=x² +6x -3x -18
=x(x + 6) -3(x + 6)
=(x -3)(x + 6)
now you see (x -3) is common factor of given polynomials .
so a = 3
Answered by
2
Answer:
Step-by-step explanation:
x² -x -6
=x² -3x +2x -6
=x(x -3) + 2(x -3)
=(x +2)(x -3)
now,
x² +3x -18
=x² +6x -3x -18
=x(x + 6) -3(x + 6)
=(x -3)(x + 6)
now you see (x -3) is common factor of given polynomials .
so a = 3
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