Math, asked by krishnagupta2207050, 11 months ago

if (x - 2/x) = 6 find the value of (x^3 -8/x^3)

Answers

Answered by PavangowdaR15
7

Answer:

234

Step-by-step explanation:(x-2/x)=(6)^3

=X^3-8/x^3-3×x+1/x=216

=x^3-8/x^3-18=216

=x^3-8/x^3=216+18

=x^3-8/x^3=234

Answered by amansharma264
7

EXPLANATION.

⇒ (x - 2/x) = 6.

As we know that,

Cubing on both sides of the equation, we get.

⇒ (x - 2/x)³ = (6)³.

⇒ (x)³ - 3(x)²(2/x) + 3(x)(2/x)² - (2/x)³ = (6)³.

⇒ x³ - (6x) + (12/x) - (8/x³) = 216.

⇒ x³ - 6(x - 2/x) - 8/x³ = 216.

Put the value of (x - 2/x) = 6 in the equation, we get.

⇒ x³ - 6(6) - 8/x³ = 216.

⇒ x³ - 36 - 8/x³ = 216.

⇒ x³ - 8/x³ = 216 + 36.

⇒ x³ - 8/x³ = 252.

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