Math, asked by yashja2006, 1 year ago

If (x-2/x) = 6, find the value of (x^3 - 8/x^3)​

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Answered by warylucknow
6

Answer:

The value of x^{3}-\frac{8}{x}^{3} is 252.

Step-by-step explanation:

The formula of (a - b)³ is:

(a-b)^{3}=a^{3}-b^{3}-3ab(a-b)

Use this relation to solve the provided problem as follows:

(x-\frac{2}{x})^{3}=x^{3}-(\frac{2}{x})^{3}-3.x.\frac{2}{x}(x-\frac{2}{x})\\6^{3}=x^{3}-\frac{8}{x}^{3}-36\\216+36=x^{3}-\frac{8}{x}^{3}\\x^{3}-\frac{8}{x}^{3}=252

Thus, the value of x^{3}-\frac{8}{x}^{3} is 252.

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