Math, asked by DeepakRock26, 3 months ago

if x^2+x-6=(x+3)(x+k)=___________​

Answers

Answered by Thor610
1
2
In this equation as we have to solve for k x^2+x-6=(x+3)(x+k)
x^2+x-6= x^2+3x+kx+3k
As we can see 6=3k
So
K=2
Answered by Expert0204
7

\huge\tt\underline\red{Ans}\underline {w}\underline\purple{e}\underline{r}\orange {:}

Value of k = 5

\huge \underbrace \mathfrak \red{Explanation}

By algebraic identity :

\boxed { (x+a)(x+b) = x^{2}+(a+b)x+ab}

\begin{gathered} Given \\x^{2}+kx+6 \\= (x+2)(x+3)\\=x^{2}+(2+3)x+2\times 3\\=x^{2}+5x+6\end{gathered}

Therefore,

x²+kx+6=x² +5x+6

Compare both sides of the equation, we get

k = 5

Hope it will help you

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