Question

if x-2,x,x+3 are first no if g.p then find x​

Answer 1

Answer:

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Answer 2

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THERE IS YOUR ANSWER....{∆}

FOR AN GP THE RATIO OF THE TERM WITH IT'S PRECEEDING TERM IS CONSTANT......{¶}

$acc \: to \: your \: question \\ \\ \frac{x}{x - 2} = \frac{x + 3}{x} \\ \\ {x}^{2} = (x - 2)(x + 3) \\ {x}^{2} - (x - 2)(x + 3) = 0 \\ {x}^{2} - ( {x}^{2} - 2x - 6 + 3x) = 0 \\ {x}^{2} - {x}^{2} - x + 6 = 0 \\ - x + 6 = 0 \\ - x = - 6 \\ \\ x = 6 \: is \: the \: answer$

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