if X/2+ y= 0.8 and 7/( X+y/2) = 10 the value of X+ y is
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Answer: The given pair of equations are: x 2 x2 + y = 0.8 ⇒ x + 2y = 1.6…… (a) 7/(x + y 2 y2) = 10 ⇒7 = 10(x + y 2 y2) ⇒7 = 10x + 5y Let’s, multiply LHS and RHS of equation (a) by 10 for easy calculation So, we finally get 10x + 20y = 16 . (i) And, 10x + 5y = 7 ……(ii) Now, subtracting two equations we get, ⇒ (i) – (ii) 15y = 9 ⇒ y = 3 5 35 Next, putting the value of y in the equation (i) we get, x = [16 − 20(3/5)]/10 ⇒ ( 16 – 12 ) 10 (16–12)10 = 4 10 410 ∴ x = 2 5 25 Thus, the value of x and y obtained are 2 5 25 and 3 5 35 respectively. Read more on Sarthaks.com - https://www.sarthaks.com/625382/solve-the-following-system-of-equations-x-2-y-0-8-7-x-y-2-10
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