Question

If x=(-2), y=1-(-11), z=6+(-2)+(-3), then find the following÷
(i)x^2y-1
(ii)yx^3z^2
(iii)2xz+(-3)z^2
(iv)7(y^2)×11x^2
(v)(x^2)(y^3)

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Answer 1

Step-by-step explanation:

Given:-

x=(-2), y=1-(-11), z=6+(-2)+(-3)

To find:-

Find the following÷

(i)x^2y-1

(ii)yx^3z^2

(iii)2xz+(-3)z^2

(iv)7(y^2)×11x^2

(v)(x^2)(y^3)

Solution:-

Given that :

x = -2

y= 1-(-11) = 1+11 = 12

z = 6+(-2)+(-3)=6-2-3=6-5=1

i) The value of x^2y-1

=>(-2)^2×12-1

=>4×12-1

=>48-1

=>47

ii) The value of yx^3z^2

=>(12)×(-2)^3×(1)^2

=>12×(-8)×1

=>-96

iii)The value of 2xz+(-3)z^2

=>2×(-2)×(1)+(-3)×(1)^2

=>-4+(-3)(1)

=>-4-3

=>-7

iv) The value of 7(y^2)×11x^2

=>7×(12)^2×11×(-2)^2

=>7×144×11×4

=>44352

v)The value of (x^2)(y^3)

=>(-2)^2×(12)^3

=>4×1728

=>6912

Answer:-

Answers for the following are :

i) 47

ii) - 96

iii) -7

iv)44352

v)6912