Question

if x = "-2" , y = 1 and Z = 3 , then verify , a) ( x+y+z)^2=x^2+y^2+y^2+z^2+2xy + 2yz+2zx​

Answer 1

Answer:

4

Step-by-step explanation:

Hope it helps! Please mark me as the Brainliest!!!

Answer 2

Answer:

Step-by-step explanation:

Given that,

x = - 2, y = 1 and z = 3.

L.H.S. = ( x + y + z )² = ( -2 + 1 + 3 )² = (4 - 2 )² = (2)² = 4.

R.H.S. = x² + y²+z² + 2xy + 2yz + 2zx

= (-2)² + (1)² + (3)² + 2 (-2)(1) + 2 (1)(3) + 2 (3)(-2)

= 4 + 1 + 9 + (-4) + 6 + (-12)

= 4 + 1 +9 - 4 + 6 - 12 (∵ + × - = - )

=20 - 16 (∵ 4 + 1 +9 + 6 = 20 and - 4 - 12 = - 16 )

= 4 .

∴ L.H.S. = R.H.S. is proved.