Question

If x = 2 , y= 1 and z = -3 , then x^3 + y^3 + z^3 - 3xyz is equal to ​

Answer 1

Answer:

$x = 2 \\ y = 1 \\ z = - 3 \\ \\ {x}^{3} + {y}^{3} + {z}^{3} - 3 \times x \times y \times z \\ \\ = {2}^{3} + {1}^{3} + { - 3}^{3} - 3.2.1. - 3 \\ \\ = 8 + 1 - 27 + 18 \\ \\ = 0$

Answer 2

Answer:

0

Step-by-step explanation:

${2}^{3} + {1}^{3} + ( { - 3}^{3} ) - 3 \times x \times y \times z \\ 8 + 1 + ( - 27) + 18 \\ = 9 - 27 + 18 \\ = - 18 + 18 \\ = 0$