Math, asked by blackpanther7299, 4 months ago

if x =2 y =1 z=3 find the value of 6yz(x²y²+2yz

Answers

Answered by hrishikeshsharma42

0

Answer:

6yz(x²y²+2yz)

6.1.3(2².1²+2.1.3)

18(4+6)

18(10)

Ans:180

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