if x^2+y^2=1,then what is 1+x+it/1+x+-iy equal to
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1+x+iy/1+x-iy= (1+x+iy)^2/(1+x)^2+y^2. (denominator is rationalized)
=1+x^2+(iy)^2+2x+2xiy+2iy/1+x^2+2x+y^2
= 1+x^2-y^2+2x-2xiy+2iy/2+2x
=2+x^2-,y^2+2x-2(xiy-iy)/2+2x
=
proceeding it,u will get ur answer
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