If x^2+y^2=10xy prove that 2log{x+y}=logx +logy+ 2log2 +log3
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Step-by-step explanation:
x^2+y^2=10xy
2log{x+y} = logx +logy+ 2log2 +log3
LHS=2log{x+y}
=log(x+y)²
=log ( x²+y²+2xy
=log(10xy+2xy)=log(12xy)
=log( xy*4*3)
=log x+log y log 4+log 3
=log x+ log y+log 2²+log 3
=log x+ log y+2log 2+log 3=RHS
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