Question

If X^2+Y^2=13 and xy=6, find the value of X+Y​

Answer 1

Answer:

(x+y)² = x²+y²+2xy

(x+y)²2 = 13 + 2 x 6

(x+y)² = 25

(x+y) = √25

x+y = 5

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(x-y)² = x²+y² - 2xy

(x-y)² = 13-2 x 6

(x-y)² = 1

(x-y)=√1

x - y = ± 1 [-1 or +1]

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