if x^2+y^2=13 and xy=6 find x^4+y^4
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x⁴ + y⁴ = 97
Step-by-step explanation:
x² + y² = 13
Squaring both the sides,
(x² + y²)² = (13)²
→ (x²)² + (y²)² + 2x²y² = 169
• x²y² = (xy)²
From Question, xy = 6
Hence, x²y² = (xy)² = (6)²
→ x⁴+ y⁴ + 2(6)² = 169
→ x⁴+ y⁴ + 2(36) = 169
→ x⁴+ y⁴ + 72 = 169
→ x⁴+ y⁴ = 169 - 72
→ x⁴+ y⁴ = 97
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Identity used :
• (a + b)² = a² + b² + 2ab
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