Question

if x^2+y^2=13 and xy=6, find x+y using identity​

Answer 1

Answer:

▶Here's your answer

⏩Given,

${x}^{2} + {y}^{2} = 13 \: \: \: and \: xy = 6 \\ \\ x + y = find$

⏩By using identity

${x}^{2} + {y}^{2} = (x + y)( {x}^{2} + {y}^{2} </strong><strong>-</strong><strong> xy) \\ \\ 13 = (x + y)(13 </strong><strong>-</strong><strong> 6) \\ \\ 13 = (x + y)(</strong><strong>7</strong><strong>) \\ \\ 13 </strong><strong>-</strong><strong>7</strong><strong> = (x + y) \\ \\ </strong><strong>6</strong><strong> = (x + y)$

⏩The answer is 6...

Hope it helps ✌

Answer 2

$\huge\mathfrak{\red{\underline{Answer:-}}}$

$\mathfrak{\underline{Given:-}}$

$\mathfrak x{}^{2}+y{}^{2}=13$

$\mathfrak xy=6$

$\mathfrak( x+y){}^{2}=x{}^{2}+y{}^{2}+2xy$

$\sf (x+y){}^{2}=13+2×6$

$\sf (x+y){}^{2}=25$

$\sf x+y=\sqrt{25}$

$\sf x+y=5$