Question

If x^2+y^2=13 and xy=6 then find the value of x^4+y^4.

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Answer 1

(1)

(x+y)² = x²+y²+2xy

(x+y)² = 13+2(6)

(x+y)² = 13+12

(x+y)² = 25

(x+y) = √25

x+y = 5

(2)

(x-y)² = x²+y²-2xy

(x-y)² = 13-2(6)

(x-y)² = 13-12

(x-y) = √1

x-y = ±1

(3)

x⁴+y⁴ = (x²)²+(y²)²

x⁴+y⁴ = (x²+y²)²-2(x²)(y²)

x⁴+y⁴ = 13²-2(xy)²

x⁴+y⁴ = 169-2(6)²

x⁴+y⁴ = 169-2(36)

x⁴+y⁴ = 169-72

x⁴+y⁴ = 97

Hope it helps....

Answer 2

Hope it helps u definitely