Question

If x^2 + y^2 = 14 and xy = 5, find the value of (x + y)^2

Answer 1

Answer:

As We Know ,

( A + B ) ^ 2 = A^2 + B^2 + 2AB

So ,

( x + y ) ^2 = x ^2 + y ^2 + 2xy

Given : -

x^2 + y^2 = 14 & xy = 5

Now , By Putting the Given Values : -

( x + y ) ^2 = 14 + 2 ( 5 )

= 14 + 10

= 24