If x^2-y^2=15 and x+y=3, find the value of (x-y)^3.
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Given:
x²-y²=15
x+y=3
To find:
(x-y)³
Answer:
x²-y²=15
=>(x+y)(x-y)=15
=>3(x-y)=15 [Given x+y=3]---------(i)
=> (x-y)=5---------(ii)
Adding (i) and (ii)
2x=8
=> x=4
Put in (ii)
4-y=5
=>y=-1
(x-y)³=x³-y³-3xy(x-y)
=64+1+12(5)
=65+60
=125
Ans. = 125
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