Question

if (x^2-y^2)=18 and (x-y)=3 find the value of 16x^2y^2
a. 27
b. 81
C.243
d. 729
​

Answer 1

Answer:

d

Step-by-step explanation:

x²-y² = 18

(x+y)(x-y) = 18

3×(x+y) =18

(x+y) =18/3 =6

x+y=6

x-y =3

x=9/2

y = 3/2

16×x²×y² = 16×9²/2²×3²/2² = 27² = 729