Question

if x^2+y^2+2^2=16 and xy+yz+zx=10 find x+y+z​

Answer 1

Answer:

x^2+y^2+2^2=16

xy+yz+zx=10

(x+y+z)^2=x^2+y^2+2^2+2(xy+yz+zx)=16+20=36

x+y+z=6