if (x^2+y^2)^2=xy , find dy/dx.
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hii .......
here is your answer.......
d (x^2+y^2)^2/dx^2+y^2.dx^2/dx+dy^2/dx=y+x.dy/dx
=》2 (x^2+y^2).2x+2y.dy/dx=y+x.dy/dx
=》2y.dy/dx-x.dy/dx= -2 (x^2+y^2).2x+y
=》dy/dx= [-2 (x^2+y^2).2x+y]/2y-x
here is your answer.......
d (x^2+y^2)^2/dx^2+y^2.dx^2/dx+dy^2/dx=y+x.dy/dx
=》2 (x^2+y^2).2x+2y.dy/dx=y+x.dy/dx
=》2y.dy/dx-x.dy/dx= -2 (x^2+y^2).2x+y
=》dy/dx= [-2 (x^2+y^2).2x+y]/2y-x
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