If x^2+y^2=221 and x-y=1 then find the value of x^3-y^3
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Hey,
(x-y)2=x2+y2-2xy
(1)2=221-2xy
1=221-2xy
2xy=221-1
2xy=220
xy=220/2
xy=110
x3-y3=(x-y) (x2+xy+y2)
=1 (x2+y2+xy)
=1 (221+110)
=331
therefore x3-y3=331
HOPE IT HELPS YOU:-))
(x-y)2=x2+y2-2xy
(1)2=221-2xy
1=221-2xy
2xy=221-1
2xy=220
xy=220/2
xy=110
x3-y3=(x-y) (x2+xy+y2)
=1 (x2+y2+xy)
=1 (221+110)
=331
therefore x3-y3=331
HOPE IT HELPS YOU:-))
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