Question

If x^2+y^2=23 then prove that 2log(x+y)=2log5+logx+logy


pls answer to this question

i will mark you brainliest.......pls frnds​

Answer 1

(x+y)2 = x2 + 2xy + y2 = 25xy

log(x+y)2 = 2log(x+y)

But, log(x+y)2 = log(25xy)

= log25 + logx + logy

= log(52) + logx + logy

= 2log5 + logx + logy

So, 2log(x+y) = 2log5 + logx + logy

2(log(x+y) - log5) = logx + logy

log(x+y) - log5 = ½[logx + logy]

log{(x+y)/5} = ½[logx + logy]


Please mark me as brainlist

Answer 2

Answer:

answer for the given problem is given