Question

if x^2+y^2=26 and xy=3,find the value of x^4+y^4.​

Answer 1

Answer:

x^2+y^2=26 ,xy=3 ,x^4+y^4= (x2+y2) +(x2+y2) (26+3)+(26+3)

29+29=58 ans

Answer 2

Answer:

X^2 + y^2 = 26

x y = 3

squaring both sides

x^2 y ^2 = 9

( x ^2 + y^2)^2 = x^4 + y^4 + 2x^2 y^2

26 ^2 = x^4 + y^4 + 2 (9)

676 - 18 = x^4 + y^4

x^4 + y^4 = 658

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