Math, asked by archiarya, 5 months ago

if x^2+ y^2=26 and xy =3 ,find the value of : x^4 +y^4​

Answers

Answered by Anonymous
4

xy=3\\x=3/y\\

substitute the value of x in e.

(3/y)^2+y^2=26\\9/y^2+y^2=26\\

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