Question

If x^2+y^2=26and xy=3,find the value of x-y

Answer 1

Answer:

$Value \: of \: x-y =± 2\sqrt{5}$

Step-by-step explanation:

Given x²+y² = 26 ---(1)

xy = 3 ----(2)

$(x-y)^{2}\\= x^{2}+y^{2}-2xy\\=26-2\times 3\\=26-6\\=20$

$x-y = ±\sqrt{20}\\=±\sqrt{2\times 2\times 5}\\=±2\sqrt{5}$

Therefore,

$Value \: of \: x-y =± 2\sqrt{5}$

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