Math, asked by arjunjayan2435, 11 months ago

If x^2+y^2=26and xy=3,find the value of x-y

Answers

Answered by mysticd
0

Answer:

 Value \: of \: x-y =± 2\sqrt{5}

Step-by-step explanation:

Given + = 26 ---(1)

xy = 3 ----(2)

 (x-y)^{2}\\= x^{2}+y^{2}-2xy\\=26-2\times 3\\=26-6\\=20

 x-y = ±\sqrt{20}\\=±\sqrt{2\times 2\times 5}\\=±2\sqrt{5}

Therefore,

 Value \: of \: x-y =± 2\sqrt{5}

•••♪

Similar questions