Question

if x^2+y^2=27 and xy=1 then find value of (x-y)​

Answer 1

Answer:

5

Step-by-step explanation:

Given,

${x}^{2} + {y}^{2} = 27$

and

$xy = 1$

We know that,

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

Substituting the values, we get,

${(x - y)}^{2} = 27 - 2 \times 1$

${(x - y)}^{2} = 25$

$(x - y) = \sqrt{25}$

$(x - y )= 5$

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