Question

if x^2 + y^2 = 28, and xy = 14, what is x^2 - y^2

Answer 1

Answer:

0

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Answer 2

Answer:

0

Step-by-step explanation:

xy=14

y=14/x

Substituting

x^2+ (14/x)^2=28

x^2 +196/x^2=28

x^4+196=28x^2

x^4-28x^2+196=0

x^2-14x^2-14x^2-196=0

(x^2-14)(x^2-14)=0

(x^2-14)=0

x^2-14=0

x^2=14

Substituting again

x^2 +y^2=28

14+y^2=28

y^2=28-14

y^2=14

x^2-y^2=14-14=0

0 is your answer.

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