Question

If x^2+y^2=29 & xy=10;find
x+y/x-y can u answer it by step by step?​

Answer 1

Step-by-step explanation:

here is your answer please mark Brainlest

Answer 2

Answer:

Step-by-step explanation:

$given,\\x^{2} +y^{2}=29 \\xy=10\\then,2xy=20\\find:\\\frac{x+y}{x-y} \\SOLUTION:\\(x+y)^{2}=x^{2} +y^{2}+2xy\\ (x+y)^{2}=29+20\\(x+y)^{2}=49\\x+y=\sqrt{49}\\x+y=7.....i\\\\\\(x-y)^{2}=x^{2} +y^{2} -2xy\\(x-y)^{2}=29-20\\(x-y)^{2}=9\\x-y=\sqrt{9}\\ x-y=3.....ii\\\\\frac{x+y}{x-y}=\frac{7}{3} \\\frac{x+y}{x-y}=2\frac{1}{3}$hope it helps u....