Question

if x^2+y^2=29 and xy =10 then find the value of x^3-y^3

Answer 1

Hope it helps you:):))

Answer 2

Answer:

Step-by-step explanation:

x²+y²=29

xy=10

we know that ,

(x-y)²=x²+y²-2xy

        =29-2*10

        =29-20

        =9

x-y=√9

     =3

now,

(x-y)³=x³-y³-3xy(x-y)

(3)³=x³-y³-3*10*3

27=x³-y³-90

x³-y³=27+90

       =117