if x^2+y^2=29 and xy =2, find the value of x-y
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Answered by
1
Answer:
x-y = -5
Step-by-step explanation:
we know that,
x²+y²-2xy = (x-y)²
so , now substitute the given values in equation
we get , => 29-2(2) = (x-y)²
=> 29-4 = (x-y)²
=> 25 = (x-y)²
=> √25 = (x-y)
=> 5 = (x-y)
=> -5 = (x-y)
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Answered by
0
Answer:
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